Thread: Sementation fault in GCC when using pointer

hi every body.i'm working on gcc writing program. encountered problem after ran program. mean it's compiled in run time gives me segmentation fault error. here code::

php code:

#include<stdio.h>
#include<string.h>
int main()
{
  char *string="";
  char *string1="";
  scanf("%s",string);
  scanf("%s",string1);
  printf("%s",string);
  printf("%s",string1);
  return 0;
} 


finally when i've changed definition of string of code below code works fine

php code:

char string[1000];
char string1[1000]; 


i wanna know can use pointer string or not????
machine runs in ubuntu 11.04 x64

posted k_mp

hi every body.i'm working on gcc writing program. encountered problem after ran program. mean it's compiled in run time gives me segmentation fault error. here code::

php code:

#include<stdio.h>
#include<string.h>
int main()
{
  char *string="";
  char *string1="";
  scanf("%s",string);
  scanf("%s",string1);
  printf("%s",string);
  printf("%s",string1);
  return 0;
} 


finally when i've changed definition of string of code below code works fine

php code:

char string[1000];
char string1[1000]; 


i wanna know can use pointer string or not????
machine runs in ubuntu 11.04 x64

you can use pointer have make point allocated memory. char *string="" makes point 1 byte ('\0'). have use:

code:

#include <malloc.h>  char *string; string=malloc(1000);

but in c, pointers , arrays same concept. when declare array, variable holds array pointer first element of array, valid:

code:

#include <stdio.h> #include <stdlib.h>  int main(int argc, char **argv){     char x1,x2;     char *string1="abcdefgh";     x1=string1[5];      x2=*(string1+5);      printf("%c =? %c\n",x1,x2);      char string2[]="abcdefgh";     x1=string2[6];      x2=*(string2+6);      printf("%c =? %c\n",x1,x2);      return 0; }

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